Andre Poenitz wrote:
> On Thu, Jan 30, 2003 at 11:55:07AM +0000, Angus Leeming wrote:
>> > Concerning cheapness:
>> >
>> > y=${x%<*}
y=`echo $x | cut -d '<' -f 1`
>> > translator=${y#*}
translator=`echo $y | cut -d ' ' -f 2-`
>> > y=${x#*<}
y=`echo $x | cut -d '<' -f 2`
>> > email=${y%>*}
email=`echo $y | cut -d '>' -f 1`
Got it. I can do conditional substitution like this with vanilla sh
but neither '%' nor '#' operations are available to me. Shame, they
_are_ really nice.
>> Never seen nothing like this. Can you explain it to me? It looks
>> like gook to me ;-)
>
> man bash
> /##
>
> ${parameter#word}
> ${parameter##word}
> The word is expanded to produce a pattern just as
> in pathname expansion. If the pattern matches the
> beginning of the value of parameter, then the
> result of the expansion is the expanded value of
> parameter with the shortest matching pattern (the
> ``#'' case) or the longest matching pattern (the
> ``##'' case) deleted. [...]
>
> I learned about it only a few weeks ago and I _really_ like it.
> Using bash is no restriction for me.
>
>
>> Give me a little example of it in action and I'll try it here with
>> dumn old vanilla sh.
>
> I don't think sh will work.
>
> Andre'
>
--
Angus
