> On Oct 12, 2019, at 10:10 AM, Ryan Schmidt <ryandes...@macports.org> wrote:
> 
> On Oct 11, 2019, at 23:11, Andrew Hartung wrote:
> 
>> On Oct 11, 2019, at 9:39 PM, Ryan Schmidt wrote:
> 
>>> On Oct 10, 2019, at 22:58, Andrew Hartung wrote:
>>> 
>>>> 
>>>> Warning: All compilers are either blacklisted or unavailable; defaulting 
>>>> to first fallback option
>>> 
>>> llvm, clang, and lldb are all part of the same software package.
>>> 
>>> Different ports impose different restrictions on the versions of compilers 
>>> they can be built with. According to the llvm-9.0 portfile, llvm-9.0 and 
>>> clang-9.0 blacklist clang < 602 while lldb-9.0 blacklists clang < 700.
>>> 
>>> The message you received means that, after applying the blacklist, no 
>>> suitable compiler remains. That should not be the case with Xcode 10; you 
>>> should have clang 1000 or newer, which should be fine. What version of 
>>> clang do you actually have? Run
>>> 
>>> /usr/bin/clang --version
>>> 
>>> to find out. If it's less than 1000, try (re)installing the command line 
>>> tools.
>>> 
>>> If that's not it, the compiler blacklist versions portgroup was recently 
>>> changed. Maybe in doing so we introduced a bug.
>>> 
>> 
>> ~ $ /usr/bin/clang --version
>> Apple clang version 11.0.0 (clang-1100.0.33.8)
>> Target: x86_64-apple-darwin18.7.0
>> Thread model: posix
>> InstalledDir: 
>> /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin
> 
> Clang 11 goes with Xcode 11 but you said you have Xcode 10. You should either 
> upgrade to Xcode 11 to match your clang version (I don't recommend this due 
> to the many problems we've seen with SDK paths) or you should downgrade your 
> Clang version (that is to say, your command line tools version) to match your 
> Xcode version.
> 


How do I do that?



> 
>> I had not changed/updated anything related to xcode since I had last 
>> accepted the xcode license, so maybe there has been a bug introduced.
> 
> Possibly. I am not able to investigate this right now. Maybe somebody else 
> can.

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