You might also try using the Mailman command "find_member" in ~mailman/bin. This command finds all lists that a specified user is on.
To let ordinary users run it, look into implementing sudo. Sudo is a package that lets users run programs as a specified other user. In this case your users would be running the command as the user mailman. Of course you could just let the users su as mailman or leave a process open that runs as the user mailman and provides the info folks ask for... HtH, Jon Carnes ----- Original Message ----- From: "Greg Ward" <[EMAIL PROTECTED]> To: "Kiat Huang" <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Tuesday, October 02, 2001 2:09 PM Subject: Re: [Mailman-Users] getting a subscriber's lists > On 02 October 2001, Kiat Huang said: > > Is there a way through the web interface or other means (say as the > > mailman admin, or a user not root (linux)) that can list all the lists a > > given user is subscribed to? > > This works for me as root (using bash): > cd ~mailman > for list in lists/* ; do > ./bin/list_members $list | grep -s $address && echo $list > done > > Any user in group "mailman" should be able to run this as well. It's > inefficient, but as long as you don't have 100 lists with 10000 > subscribers each, it shouldn't be too painful. > > Greg > -- > Greg Ward - software developer [EMAIL PROTECTED] > MEMS Exchange http://www.mems-exchange.org > > ------------------------------------------------------ > Mailman-Users maillist - [EMAIL PROTECTED] > http://mail.python.org/mailman/listinfo/mailman-users ------------------------------------------------------ Mailman-Users maillist - [EMAIL PROTECTED] http://mail.python.org/mailman/listinfo/mailman-users
