On Tue, 3 May 2005, Staven Bruce wrote: > I know this topic pops up fairly regularly, however I was unable to find an > answer to my specific question going through the archives and the FAQ's. I > want to create a script that will output to a file a list of all subscribers > e-mail addresses, the list they subscribe to, and their associated > password. However, the issues I have run into are as follows: > > -- The standard script that requires nmh at > <http://www.python.org/cgi-bin/faqw-mm.py?req=show&file=faq04.006.htp> uses > the /var/lib/mailman directory which does not exist in my installation of > Mailman 2.1.5 on Red Hat Enterprise 3.0. > > -- I can get list membership addresses using the > /var/mailman/bin/list_members script, however I have to specifcy each list > individually and I can not receive the password. In addition, I would have > to change the script everytime a new list was created. > > Does anyone have any suggestions on scripting this functionality?
Seeing how you can get subscribers email from list_members and lists they're subscribed to from list_lists, we'll leave this as nothing but a scripting exercise. Once that's done, you only need get the password for users which can be gotten from running dumpdb again config.pck of each list and grep -w on the email address. =-=-=-=-=-=-=-=-=-=- generated by /dev/dave -=-=-=-=-=-=-=-=-=-=-=-= David Stern University of Maryland Institute for Advanced Computer Studies ------------------------------------------------------ Mailman-Users mailing list Mailman-Users@python.org http://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://www.python.org/cgi-bin/faqw-mm.py Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: http://mail.python.org/mailman/options/mailman-users/archive%40jab.org Security Policy: http://www.python.org/cgi-bin/faqw-mm.py?req=show&file=faq01.027.htp