* Melinda Gilmore <[EMAIL PROTECTED]> wrote: > Has anyone out there put together and scripts that might extract out owners > and subscribers to a list. Where you could see all the list and all their > subscribers in one place.
My English is not that good and I'm not really sure if I understand what you actually want to achieve, but what about something like: list_lists | awk '(NR > 1){print $1}' | while read line; do echo "List: $line" list_members -f "$line" done This assumes you (1) have shell access to the box hosting Mailman and (2) that list_lists and list_members are in your $PATH. Cheers Stefan ------------------------------------------------------ Mailman-Users mailing list Mailman-Users@python.org http://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://www.python.org/cgi-bin/faqw-mm.py Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: http://mail.python.org/mailman/options/mailman-users/archive%40jab.org Security Policy: http://www.python.org/cgi-bin/faqw-mm.py?req=show&file=faq01.027.htp