On 02/10/2009 10:20:51 AM, Brian Canty wrote:
I was wondering if anyone knows of any command you can use to find out
who is subscribed to all mailman lists.
list_lists | tail -n +2 | awk '{print $1;}' | xargs -n 1 list_members |
sort -u
Gets you all the members of all the lists.
list_lists \
| tail -n +2 \
| awk '{print $1;}' \
| xargs -n 1 bash -c 'list_members $0 | xargs -n 1 echo $0:' \
| grep f...@example.com \
| cut -d f 1
Gets you all the lists that f...@example.com is subscribed to.
Karl <k...@meme.com>
Free Software: "You don't pay back, you pay forward."
-- Robert A. Heinlein
------------------------------------------------------
Mailman-Users mailing list
Mailman-Users@python.org
http://mail.python.org/mailman/listinfo/mailman-users
Mailman FAQ: http://wiki.list.org/x/AgA3
Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/
Unsubscribe:
http://mail.python.org/mailman/options/mailman-users/archive%40jab.org
Security Policy: http://wiki.list.org/x/QIA9
