> On 17 May 2014, at 5:28 am, "Mark Sapiro" <[email protected]> wrote: > >> On 05/16/2014 11:45 AM, Ryan Stasel wrote: >> >> Can't seem to find an answer for this, but I'd imagine it would involve >> list_lists... but we have an employee leave rather poorly, and while I was >> able to remove them from all the lists with remove_members --fromall >> <email>, I can't seem to find a way to remove them from all lists approved >> senders (in sender filters) lists. >> >> Is there a way to do this? > > > See the script at <http://www.msapiro.net/scripts/non_members>.
Is this the same filter as used on the moderation page where it says "Add [email protected] to one of these filters" if I select the "Accepts" option? If so, is a script the only way to access its contents? Peter Shute ------------------------------------------------------ Mailman-Users mailing list [email protected] https://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: https://mail.python.org/mailman/options/mailman-users/archive%40jab.org
