On Mon, 2014-06-16 at 11:01 -0700, Mark Sapiro wrote: > This list is for Mailman users, not Listserv(r) users. See > <http://wiki.list.org/display/DOC/Mailman+is+not+Listserv> > > That said, and assuming you really mean Mailman and not Listserv(r), > what is your question? > > If you mean is there a way for a list admin to see what other lists in > this installation a user is subscribed to, no. The site admin can go to > the user's options page and list the user's other subscriptions if the > site has set 'ALLOW_SITE_ADMIN_COOKIES = Yes' in mm_cfg.py, and the site > admin can use Mailman's bin/find_member command to find the lists a user > is subscribed to, but an ordinary list owner can't do these. > > If you mean is there a way for a list admin to see what other lists she > is an admin of, see the FAQ at <http://wiki.list.org/x/5YA9>. > A lot of creative jiggery-pokery can be done using ~mailman/bin/withlist at a CLI prompt. Without going into details (which are very detailed) you can obtain a list of lists on the server using Mailman.Site.get_listnames() and search for subscribers within each element of the returned list of lists. This stuff can be scripted and run from a web UI if you wish. Some knowledge of Python is necessary, otherwise YMMV :)
-- Lindsay Haisley | "Everything works if you let it" FMP Computer Services | 512-259-1190 | --- The Roadie http://www.fmp.com | ------------------------------------------------------ Mailman-Users mailing list Mailman-Users@python.org https://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: https://mail.python.org/mailman/options/mailman-users/archive%40jab.org