On 07/05/2014 08:03 AM, Reinhard Klein wrote: > Hi to all > We have just started to run a Mailing list with nearly 1000 subscribers. > If I go to list the subcribers in the admin web interface, I have only > found the possibilty to search subscribers by name or e-mail adress to > list them, or list all by entering a star (*)
You can also search by partial name or email address, e.g, search for yahoo.com to find all members with yahoo.com addresses[1]. You can also search for members whose name or address matches a regular expression pattern, e.g. ^j.*com$ to find members whose name or address starts with 'j' and ends with 'com'. All matches are case insensitive. see the 'Find member' help link for documentation of the regular expression syntax. > Is there a possibility to search by the content of the other subscriber > list columns like "nomail" to see who has nomail = on for any reason. > If so, what is the search syntax for that. Not directly from the web UI. If you have access to Mailman's command line tools, you can use Mailman's bin/list_members for this, e.g. bin/list_members --nomail LISTNAME See 'bin/list_members --help' for more. If you only have web access, the script at <http://www.msapiro.net/scripts/mailman-subscribers.py> and/or the FAQ at <http://wiki.list.org/x/aYA9> may help. -- Mark Sapiro <m...@msapiro.net> The highway is for gamblers, San Francisco Bay Area, California better use your sense - B. Dylan ------------------------------------------------------ Mailman-Users mailing list Mailman-Users@python.org https://mail.python.org/mailman/listinfo/mailman-users Mailman FAQ: http://wiki.list.org/x/AgA3 Security Policy: http://wiki.list.org/x/QIA9 Searchable Archives: http://www.mail-archive.com/mailman-users%40python.org/ Unsubscribe: https://mail.python.org/mailman/options/mailman-users/archive%40jab.org
