On 10/7/21 2:35 PM, McGuire, Tommy M. (MSFC-IS90)[EAST2] via
Mailman-Users wrote:
Suppose you have two lists: [email protected] and [email protected] and
that you want destination to be subscribed to source. In addition to making
destination a member of source (so source sends email to destination), what do
you need to put as a non-member in destination?
Should it be '[email protected]' or '[email protected]'?
Email that source sends out has a from address of "source-bounces@..." but is the
"-bounces" stripped off before the moderation processing?
Yes, I'm trying to figure out why one particular sub-list isn't getting email.
These questions are answered at https://wiki.list.org/x/4030574 but
there's more to it than that.
If [email protected] has only other lists as members, it should be
defined as an umbrella list by setting General Options -> umbrella_list
to Yes. Without this, one can send a message with
Subject: password [email protected]
to [email protected] and the password for
[email protected] will be sent to that list. Setting umbrella_list
to Yes will send such notices to [email protected], but if
the [email protected] list has human members as well, this will mess up
notices to them.
Also see https://wiki.list.org/x/4030540 for info about how to use
Non-digest options -> regular_include_lists as an alternative.
--
Mark Sapiro <[email protected]> The highway is for gamblers,
San Francisco Bay Area, California better use your sense - B. Dylan
------------------------------------------------------
Mailman-Users mailing list -- [email protected]
To unsubscribe send an email to [email protected]
https://mail.python.org/mailman3/lists/mailman-users.python.org/
Mailman FAQ: http://wiki.list.org/x/AgA3
Security Policy: http://wiki.list.org/x/QIA9
Searchable Archives: https://www.mail-archive.com/[email protected]/
https://mail.python.org/archives/list/[email protected]/