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Hi David
> >---------------------------------------------------------
> >Chain input (policy ACCEPT):
> >Chain forward (policy ACCEPT):
> >target     prot opt     source                destination    
>        ports
> >MASQ       all  ------  192.168.0.0/24        anywhere       
>        n/a
> >Chain output (policy ACCEPT):
> 
> Be careful.. setting defauly policies to ACCEPT is bad in 
> terms of security.

Sure - but I'm just trying to get it working at the moment 

> 
> So I take it you have:
> 
> Internet --| ppp 194.42.225.131 |
>            |    linux ROUTER    |
>            |         eth0       |
>            |    192.168.0.168   |
>                       |
>                       |
>            +----------+-----------+
>            |                      |
>         linux box              Windows NT
>       192.168.0.165          192.168.0.108
> 

Exactly right

> >route on my router shows this :
> >-----------------------------------------------------------
> >Kernel IP routing table
> >Destination     Gateway         Genmask         Flags Metric 
> Ref    Use
> >Iface
> >194.42.225.131  *               255.255.255.255 UH    0      
> 0        0 ppp0
> >192.168.0.168   *               255.255.255.255 UH    0      
> 0        0 eth0
> >192.168.0.0     192.168.0.168   255.255.255.0   UG    0      
> 0        0 eth0
> >192.168.0.0     *               255.255.255.0   U     0      
> 0        0 eth0
> >127.0.0.0       *               255.0.0.0       U     0      
> 0        0 lo
> >default         194.42.225.131  0.0.0.0         UG    0      
> 0        0 ppp0
> 
> 
> You have two default routes here.  Thats kinda weird.
Why do you say 2 default routes?  I only see one labled default.  Are
you refering to the gateway 192.168.0.168?  I think I added that in the
"try everything and see" process ie desperation ;) 

> >route on my Linux box shows this :
> >------------------------------------------------------------
> >Kernel IP routing table
> >Destination     Gateway         Genmask         Flags Metric 
> Ref    Use
> >Iface
> >192.168.0.168   *               255.255.255.255 UH    0      
> 0        0 eth0
> >192.168.0.165   *               255.255.255.255 UH    0      
> 0        0 eth0
> >192.168.0.0     *               255.255.255.0   U     0      
> 0        0 eth0
> >127.0.0.0       *               255.0.0.0       U     0      
> 0        0 lo
> >default         192.168.0.168   0.0.0.0         UG    0      
> 0        0 eth0
> 
> why do you have host networks for 192.168.0.168 and 192.168.0.165?
> Can the Linux box ping the Linux router?
> 
Again - desperation and ignorance.  But yet, the linux box can ping the
router

> 
> NT box:
> 
> >          0.0.0.0          0.0.0.0    192.168.0.168   
> 192.168.0.108   1
> >        127.0.0.0        255.0.0.0        127.0.0.1       
> 127.0.0.1       1
> >      192.168.0.0    255.255.255.0    192.168.0.108   
> 192.168.0.108   1
> >    192.168.0.108  255.255.255.255        127.0.0.1       
> 127.0.0.1       1
> >    192.168.0.255  255.255.255.255    192.168.0.108   
> 192.168.0.108   1
> >        224.0.0.0        224.0.0.0    192.168.0.108   
> 192.168.0.108   1
> >  255.255.255.255  255.255.255.255    192.168.0.108   
> 192.168.0.108   1
> 
> I take it your NT box is using DHCP?
Yes.  Why?  Is that based on the the numbers you see, or just a guess?
Does it make any difference.  There is an NT server doing the DHCP


thanks for your time

clint

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