Hi
I swore this worked till recently:
I have
k=1:N+1 x(k+1)=x(k)+h; y(k+1)=f(x(k+1)); z(k+1)=g(x(k+1)); end
So I mark it and run indent-region
And I receive
for k=1:N+1
x(k+1)=x(k)+h; y(k+1)=f(x(k+1)); z(k+1)=g(x(k+1));
end
Which is absurd, I should have obtained
for k=1:N+1
x(k+1)=x(k)+h; y(k+1)=f(x(k+1)); z(k+1)=g(x(k+1));
end Now I run matlab-indent-sexp
And obtain again
for k=1:N+1
x(k+1)=x(k)+h; y(k+1)=f(x(k+1)); z(k+1)=g(x(k+1));
end
What is up here?
Or is the culprit GNU emacs 27?
Uwe Brauer
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