And, before someone asks, "Why are you using "h" and this line: h= [seg[0]*0.000278,seg[1]*0.000278] ax.annotate(seqnum[nshape],h)", I was using this, instead, but tried to experiment with things to try to make things work right: ax.annotate(seqnum[nshape],seg) . I usually don't "give up" and post a question unless I've tried a myriad of things, and unfortunately those things sometimes show up in the example code.
Regards, Kurt ------------------------------------------------------------------------- Check out the new SourceForge.net Marketplace. It's the best place to buy or sell services for just about anything Open Source. http://ad.doubleclick.net/clk;164216239;13503038;w?http://sf.net/marketplace _______________________________________________ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users