hmm, reading the initial email, this is not what I understood the idea would be. So let me the following : I have a dictionnary with the 7 days of week as keys (strings) and a value attached to it. I would like to plot the days of the week in x and the corresponding values in y. It amounts to a histogram of 7 bins, and to correctly labeling the ticks with the keys instead of the integer 0...6. So it becomes kind of a bar chart. See p.40 of ftp://root.cern.ch/root/doc/3Histograms.pdf for an illustration.
I would imagine that requesting to plot a dictionary would naturally mean this kind of result, but I may overlook possible ambiguities. Anyway, that is what I understood the initial question was. Johann John Hunter wrote: > On Wed, Jul 30, 2008 at 9:17 AM, stuartornum <[EMAIL PROTECTED]> wrote: > >> Hi, >> >> Wondering if anyone has done something similar and could point me in the >> right direction. >> >> I have a dictionary like this: >> >> Dict{'00:00:00':'23', '00:01:00':'29', '00:02:00':'13', '00:03:00':'78', >> '00:04:00':'45', >....> '23:59:00':54} >> >> So as you can see there is 24 hours worth of minutes, with a value attached >> to each minute. >> >> Firstly, just to note the Dictionary "Dict" is not actually in order as >> above, it is all jumbled up. >> >> However is it possible to plot a dictionary using MatPlotLib, and using the >> time along the x-axis and values up the y? >> > > You will have to extract the x and y values, and convert them from > strings to values matplotlib can understand (for example dates and > floating point numbers). Eg > > > In [30]: d = {'00:00:00':'23', '00:01:00':'29', '00:02:00':'13', > '00:03:00':'78', > '00:04:00':'45', '23:59:00':54} > > In [32]: from dateutil.parser import parse > > In [33]: items = [(parse(date), float(val)) for date, val in d.items()] > > In [34]: items.sort() > > In [35]: items > Out[35]: > [(datetime.datetime(2008, 7, 30, 0, 0), 23.0), > (datetime.datetime(2008, 7, 30, 0, 1), 29.0), > (datetime.datetime(2008, 7, 30, 0, 2), 13.0), > (datetime.datetime(2008, 7, 30, 0, 3), 78.0), > (datetime.datetime(2008, 7, 30, 0, 4), 45.0), > (datetime.datetime(2008, 7, 30, 23, 59), 54.0)] > > In [36]: dates, values = zip(*items) > > In [37]: plot(dates, values) > Out[37]: [<matplotlib.lines.Line2D object at 0xb45a5ec>] > > ------------------------------------------------------------------------- > This SF.Net email is sponsored by the Moblin Your Move Developer's challenge > Build the coolest Linux based applications with Moblin SDK & win great prizes > Grand prize is a trip for two to an Open Source event anywhere in the world > http://moblin-contest.org/redirect.php?banner_id=100&url=/ > _______________________________________________ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > ------------------------------------------------------------------------- This SF.Net email is sponsored by the Moblin Your Move Developer's challenge Build the coolest Linux based applications with Moblin SDK & win great prizes Grand prize is a trip for two to an Open Source event anywhere in the world http://moblin-contest.org/redirect.php?banner_id=100&url=/ _______________________________________________ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users