Thanks for the report.
And, this turned out to be a bug. The symbol style code was simply
ignored when its value is 3.
While the bug should now be fixed (both in the trunk and the maint.
branch), you may use marker style like (20,0,0) (or increase the first
number when symbol is large) for a workaround.
Regards,
-JJ
On Sun, Jun 21, 2009 at 1:09 PM, Thomas
Robitaille<thomas.robitai...@gmail.com> wrote:
>
> Hi,
>
> I'm trying to use the scatter method, making use of the option to specify
> the marker as a tuple. From the documentation, it would seem that specifying
> marker=(0,3,0) should draw a circle. However, this is not the case. If you
> consider the following code:
>
> import matplotlib
> matplotlib.use('Agg')
> import matplotlib.pyplot as mpl
>
> fig = mpl.figure()
> ax = fig.add_subplot(111)
> #ax.scatter([x],[y],c='red',marker=(0,3,0.))
> ax.scatter([10.],[10.],c='red',marker=(3,3,0.))
> ax.scatter([11.],[10.],c='red',marker=(6,3,0.))
> ax.set_xlim(5.,15.)
> fig.savefig('scatter.png')
>
> The first ax.scatter causes an error, the second plots a triangle, and the
> third a hexagon. However, the documentation states that (a) setting the
> second element to '3' should plot a circle, and (b) the other arguments
> should be ignored, so the first ax.scatter should not cause an error.
>
> Is this a bug, or am I misunderstanding the documentation?
>
> Thanks,
>
> Thomas
> --
> View this message in context:
> http://www.nabble.com/possible-bug-with-scatter-tp24136534p24136534.html
> Sent from the matplotlib - users mailing list archive at Nabble.com.
>
>
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