On Wed, Jul 15, 2009 at 3:23 PM, Louise
Loudermilk<louise.louderm...@gmail.com> wrote:
> Hi. I am trying to output multiple 2D graphs (subplots) in one figure
> (using pylab) for each time-step that the python code runs - basically an
> interactive graphs. We use the 'ion()' and 'imshow()' functions for this.
> I have many graphs to chose from, but say if I chose 4 graphs to output, all
> 4 will output for the 1st time step, but for every additional time step only
> the last graph will update. The first 3 will remain the same, as they were
> in the 1st time step. Has anyone has this problem? Any suggestions?
>
I'm not sure what exactly an issue here.
You want to know how to keep the first three graph during each step?
Can't you just clear the last axes, and redraw it.
e.g.,
self.subplot4.cla()
self.subplot4.imshow(...)
if you want to stick to the pylab interface (which I don't think a
good idea for application development),
sca(self.subplot4)
cla()
imshow(...)
A snippet of code does not help much.
Please take your time to create a small, standalone script that
reproduces your problem and post that on the mailing list.
Regards,
-JJ
> A portion of the O-O code is below. This function is called in another
> file. I tried to add notes where I thought they were helpful.
>
> def multi_display(self, n=4):
>
> ''' displaying multiple graphs '''
>
> ion()
> m = self.displayed_multi # four input graph names (provided when
> function is called)
> nsub = n # no. of subgraphs/time step
>
> for i in range(nsub): # for each subplot
>
> p = i +1
> exec ("self.subplot" + str(p) + " = subplot(2, 2, p)") # OR
> subplot(2,2,p)
>
> self.displayed = m[i]
> self.display_stand() # this calls the function below with
> 'self.displayed' in it.
>
> def display_stand(self): # displays individual graphs
>
> if self.displayed == 'ht': # this is only one of the four graphs (or
> subplots)
>
> vm = 0.0
> vx = 40.0
> t = 'Height (m)'
> imshow(self.old_ht, vmin = vm, vmax = vx,
> interpolation = 'nearest')
> title(t)
>
> Thanks,
> Louise
>
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