Thank you Lee. Thank you Chris and John, the problem is solved.
Chris, we did the method 1) as this was easier for us.
Sameer
On Sun, Aug 23, 2009 at 5:53 PM, John Hunter <jdh2...@gmail.com> wrote:
> On Sun, Aug 23, 2009 at 7:45 PM, Chris Barker<chris.bar...@noaa.gov>
> wrote:
>
> > This is a Bezier spline -- it can not exactly form a piece of a circle
> > (though it can get pretty close). You can probably find the math
> > somewhere for how to approximate a circle, but...
>
> somewhere like ... matplotlib.path.unit_circle (thanks to Michael D)
>
> @classmethod
> def unit_circle(cls):
> """
> (staticmethod) Returns a :class:`Path` of the unit circle.
> The circle is approximated using cubic Bezier curves. This
> uses 8 splines around the circle using the approach presented
> here:
>
> Lancaster, Don. `Approximating a Circle or an Ellipse Using Four
> Bezier Cubic Splines <http://www.tinaja.com/glib/ellipse4.pdf>`_.
> """
> if cls._unit_circle is None:
> MAGIC = 0.2652031
> SQRTHALF = np.sqrt(0.5)
> MAGIC45 = np.sqrt((MAGIC*MAGIC) / 2.0)
>
> vertices = np.array(
> [[0.0, -1.0],
>
> [MAGIC, -1.0],
> [SQRTHALF-MAGIC45, -SQRTHALF-MAGIC45],
> [SQRTHALF, -SQRTHALF],
>
> [SQRTHALF+MAGIC45, -SQRTHALF+MAGIC45],
> [1.0, -MAGIC],
> [1.0, 0.0],
>
> [1.0, MAGIC],
> [SQRTHALF+MAGIC45, SQRTHALF-MAGIC45],
> [SQRTHALF, SQRTHALF],
>
> [SQRTHALF-MAGIC45, SQRTHALF+MAGIC45],
> [MAGIC, 1.0],
> [0.0, 1.0],
>
> [-MAGIC, 1.0],
> [-SQRTHALF+MAGIC45, SQRTHALF+MAGIC45],
> [-SQRTHALF, SQRTHALF],
>
> [-SQRTHALF-MAGIC45, SQRTHALF-MAGIC45],
> [-1.0, MAGIC],
> [-1.0, 0.0],
>
> [-1.0, -MAGIC],
> [-SQRTHALF-MAGIC45, -SQRTHALF+MAGIC45],
> [-SQRTHALF, -SQRTHALF],
>
> [-SQRTHALF+MAGIC45, -SQRTHALF-MAGIC45],
> [-MAGIC, -1.0],
> [0.0, -1.0],
>
> [0.0, -1.0]],
> np.float_)
>
> codes = cls.CURVE4 * np.ones(26)
> codes[0] = cls.MOVETO
> codes[-1] = cls.CLOSEPOLY
>
> cls._unit_circle = cls(vertices, codes)
> return cls._unit_circle
>
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