Hi Paul,
Thanks a lot. That was exactly what I was looking for!
Best regards,
Markus
On Thu, Apr 7, 2011 at 1:14 AM, Paul Ivanov <pivanov...@gmail.com> wrote:
> Markus Baden, on 2011-04-06 10:18, wrote:
> > Hi,
> >
> > I draw four subplots that touch each other. Thus the "middle cross" of
> the
> > frame is drawn twice and appears to be thicker then the "outer
> rectangle". I
> > came across an old post for an custom Axes that would allow to only draw
> > part of the frame
> >
> >
> http://www.mail-archive.com/matplotlib-users@lists.sourceforge.net/msg10242.html
> >
> > However, when I run the example provided I get an "can't set attribute
> > error" (see traceback below). I use Python 2.7.1 |EPD 7.0-1 (32-bit) on
> Mac
> > OS 10.5.8, which includes matplotlib version 1.0.1.
> >
> > Is there a fix to get the custom class running again, or is there an
> > alternative way to achieve what I intend?
>
> Hi Markus,
>
> I didn't look at that code but I think the alternative you're
> looking for is
>
> ax.spines['right'].set_visible(False)
> ax.spines['bottom'].set_visible(False)
>
> where you use the appropriate locations you want changed for the
> different subplots axes.
>
> If you're going to have a lot of subplots, you can simplify the
> logic by first setting all spines to being invisible, and then
> using ax.is_first_col(), is_first_row() and the corresponding
> is_last_* methods to set the appropriate spines back to visible.
>
> Like this:
>
> #show only the outside spines
> for ax in all_axes:
> for sp in ax.spines.values():
> sp.set_visible(False)
> if ax.is_first_row():
> ax.spines['top'].set_visible(True)
> if ax.is_last_row():
> ax.spines['bottom'].set_visible(True)
> if ax.is_first_col():
> ax.spines['left'].set_visible(True)
> if ax.is_last_col():
> ax.spines['right'].set_visible(True)
>
> best,
> --
> Paul Ivanov
> 314 address only used for lists, off-list direct email at:
> http://pirsquared.org | GPG/PGP key id: 0x0F3E28F7
>
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