Here is how am solving this problem. It isn't terribly fast either, but
it works for me. I wrote something with pygame that was faster, but it
had its own set of problems.
Tom
---
import numpy as np
import pylab
class plotter:
def __init__(self, im, i=0):
self.im = im
self.i = i
self.vmin = im.min()
self.vmax = im.max()
self.fig = pylab.figure()
pylab.gray()
self.ax = self.fig.add_subplot(111)
self.draw()
self.fig.canvas.mpl_connect('key_press_event',self.key)
def draw(self):
if self.im.ndim is 2:
im = self.im
if self.im.ndim is 3:
im = self.im[...,self.i]
self.ax.set_title('image {0}'.format(self.i))
pylab.show()
self.ax.imshow(im, vmin=self.vmin, vmax=self.vmax,
interpolation=None)
def key(self, event):
old_i = self.i
if event.key=='right':
self.i = min(self.im.shape[2]-1, self.i+1)
elif event.key == 'left':
self.i = max(0, self.i-1)
if old_i != self.i or old_j != self.j:
self.draw()
self.fig.canvas.draw()
def show(im, i=0):
plotter(im, i)
On 08/17/2011 01:26 PM, Keith Hughitt wrote:
> I'm also looking into a similar issue, and would be interested to see
> what approaches others have taken.
>
> Has anyone found a good framework-independent solution?
>
> Keith
>
> On Wed, Aug 10, 2011 at 5:15 PM, David Just <just.da...@mayo.edu
> <mailto:just.da...@mayo.edu>> wrote:
>
> I have an array of images stored as an array of numpy arrays. I
> need to be able to efficiently scroll through that set of images.
> My first attempt at doing this goes something like this:
>
> --init--
>
> self.ax <http://self.ax> = pyplot.imshow(imgdta[0],
> interpolation='spline36', cmap=cm.gray, picker=True) # draw the
> plot @UndefinedVariable
> pyplot.axes().set_axis_off()
> self.fig = self.ax.get_figure()
> self.canvas = FigureCanvasGTKAgg(self.fig)
>
> --onscroll--
> self.ax.set_array(imdta[n]) # 0 < n < num_images
> self.canvas.draw()
>
>
> This method of changing the image data does not seem to be very
> preferment. It takes ~.25 seconds to go from one image to the next.
> Can anybody suggest a faster way? This also ends up in a canvas
> that’s much larger than I need, is there a better way to define my
> view area?
>
>
> Thank you,
> Dave.
>
>
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