2011/9/30 Александров Петр <petr_aleksand...@mail.ru>
> How to make a plot of a discontinuous 1d function without line at a
> function jump. An example is shown on a picture. This was plotted by:
> import numpy
> from matplotlib import pyplot
> x = numpy.linspace(-1.0, 1.0, 100)
> y = numpy.sign(x) * numpy.cos(x)
> axes = pyplot.gca()
> axes.set_ylim(-1.1, 1.1)
> pyplot.plot(x, y)
>
>
If you happen to know where the discontinuity is, then you could do two
separate plot commands. Automatically, it is harder. Maybe something like
this would help:
threshold = 1000.0
# Use gradient instead of diff because it returns an array of the same shape
dydx = numpy.gradient(y) / numpy.gradient(x)
idx = (numpy.abs(dydx) < threshold)
axes.plot(x[idx], y[idx])
Although, that gets rid of valid data points. Another trick would be to
rebuild the x and y arrays, but with NaNs placed between datapoints that
would form the discontinuity. matplotlib automatically treats NaNs as a
indicator to break a line.
Ben Root
------------------------------------------------------------------------------
All of the data generated in your IT infrastructure is seriously valuable.
Why? It contains a definitive record of application performance, security
threats, fraudulent activity, and more. Splunk takes this data and makes
sense of it. IT sense. And common sense.
http://p.sf.net/sfu/splunk-d2dcopy2
_______________________________________________
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users
