Thanks Francesco, but I've also tried to use the "draw_frame(False)" method
with no luck.


montefra wrote:
> 
> Hi,
> 
> I usually do like this
> 
> l = ax.legend( (rects1[0], rects2[0]), ('set1', 'set2'))
> l.draw_frame(False)
> 
> Cheers,
> 
> Francesco
> 
> 2011/11/9 magurling <magurl...@gmail.com>:
>>
>> I want a legend without the black border. I've tried a few things that
>> have
>> been suggested on this forum and elsewhere to no avail. According to what
>> I've seen, it should be as simple as:
>>
>> import matplotlib.pyplot as plt
>> import numpy as np
>>
>> N = 5
>> Means1 = (20, 35, 30, 35, 27)
>> Means2 = (25, 32, 34, 20, 25)
>>
>> ind = np.arange(N)  # the x locations for the groups
>> width = 0.20       # the width of the bars
>>
>> fig = plt.figure()
>> ax = fig.add_subplot(111)
>> rects1 = ax.bar(ind, Means1, width, color='k')
>> rects2 = ax.bar(ind+width, Means2, width, color='w')
>>
>> ax.legend( (rects1[0], rects2[0]), ('set1', 'set2'), frameon=False )
>>
>> plt.show()
>>
>>
>> It all works except for "frameon=False"
>>
>> I get this:
>>
>> /usr/lib/pymodules/python2.7/matplotlib/axes.pyc in legend(self, *args,
>> **kwargs)
>>   4042
>>   4043         handles = cbook.flatten(handles)
>> -> 4044         self.legend_ = mlegend.Legend(self, handles, labels,
>> **kwargs)
>>   4045         return self.legend_
>>   4046
>>
>> TypeError: __init__() got an unexpected keyword argument 'frameon'
>>
>> I've also checked my matplotlibrc under the "Legend" section and I don't
>> see
>> a "legend.frameon" line.
>>
>> It must be something simple that I am doing wrong. Any ideas?
>> --
>> View this message in context:
>> http://old.nabble.com/legend-border%2C-frameon-keyword-tp32807933p32807933.html
>> Sent from the matplotlib - users mailing list archive at Nabble.com.
>>
>>
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> 
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-- 
View this message in context: 
http://old.nabble.com/legend-border%2C-frameon-keyword-tp32807933p32827812.html
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