Hi there,
I want to examine a vector field and therefore i used "quiver" to
visualize said field:
> import numpy as np
> import matplotlib.pyplot as plt
>
> # points
> x, y = np.meshgrid(np.arange(0, 2*np.pi, 0.1),
> np.arange(0, 1*np.pi, 0.1))
> # derivatives
> dx = -2*np.sin(x)*np.cos(y)
> dy = np.cos(x)*np.sin(y)
>
> # plot
> plt.figure()
> plt.quiver(dx, dy, color='b')
>
> # beautiful axis
> a = plt.gca()
> x_a, y_a = a.get_xaxis(), a.get_yaxis()
> a.axis('tight')
> # TODO: We should not multiply with 10 here.
> x_a.set_ticks(np.arange(0, 2*np.pi*10+1, np.pi*10/4))
> y_a.set_ticks(np.arange(0, 1*np.pi*10+1, np.pi*10/4))
> labels = [
> r'$0$',
> r'$\frac{1}{4}\pi$',
> r'$\frac{1}{2}\pi$',
> r'$\frac{3}{4}\pi$',
> r'$\pi$',
> r'$\frac{5}{4}\pi$',
> r'$\frac{3}{2}\pi$',
> r'$\frac{7}{4}\pi$',
> r'$2 \pi$']
> a.set_xticklabels(labels)
> a.set_yticklabels(labels[:5])
>
> # show
> plt.show()
(The plot looks like a double swirl, if anyone is interested in that
information)
At first I do not know why I have to multiply with 10 at the ticks, but
thats not the point.
It is much more important that I would like to set the image to a
certain width before saving. It should be both "tight" and "equal", so
after setting the width the height could be calculated automatically.
As a workaround I use the images and strech them vertically, but then
the x/y axis tick labels look strange.
So: How to set a certain width?
Thanks and a merry Christmas,
Keba
------------------------------------------------------------------------------
Write once. Port to many.
Get the SDK and tools to simplify cross-platform app development. Create
new or port existing apps to sell to consumers worldwide. Explore the
Intel AppUpSM program developer opportunity. appdeveloper.intel.com/join
http://p.sf.net/sfu/intel-appdev
_______________________________________________
Matplotlib-users mailing list
[email protected]
https://lists.sourceforge.net/lists/listinfo/matplotlib-users
