Well, not sure if that is supported, but I found a way !:
[...]
self.fig1 = Figure(figsize=(width, height), dpi=dpi)
self.fig2 = Figure(figsize=(width, height), dpi=dpi)
self.axes1 = self.fig1.add_subplot(223)
self.axes2 = self.fig2.add_subplot(221)
[...]
self.axes2.plot([0,1])
(1) self.axes2.set_figure(self.fig1)
(2) self.fig1.add_axes(self.axes2)
Note that (1) and (2) are required in that order!
From the code above, if I show the fig1, then I see axes1 and axes2 on the
figure....
Summary:
I created the axes2 independently of fig1
PS: I want to use my axes2 as an object to sent to my Qt widget (a blank
figure/canvas)
--
Emmanuel
________________________________
From: Eric Firing <efir...@hawaii.edu>
To: matplotlib-users@lists.sourceforge.net
Sent: Sunday, April 1, 2012 1:36 PM
Subject: Re: [Matplotlib-users] assigning a plot object to a figure
On 03/30/2012 01:23 PM, Emmanuel Mayssat wrote:
> Hello all,
>
> I can create a figure
> and get the corresponding axes/plots
>
> for examples:
> 1/
> fig = Figure(figsize=(width, height), dpi=dpi)
> ax = gif.add_subplot(111)
>
> 2/
> fig, ax = plt.subplots()
>
> but I would like to create my plot independently from the figure and
> assign it to a figure
>
> I code I would like to do something like this
>
> my_ax = Axes(...)
> my_ax.plot(x,y)
>
>
> ax = my_ax
>
> or
>
> my_ax.set_figure(fig)
>
> How can I create the axes/plot object independently from the figure?
As far as I can see, you can't. The figure is deeply embedded in the
Axes object; that's why the figure is an argument in Axes.__init__().
> Better yet, how can I assign an axe to a figure?
I don't think you can. It looks to me like Axes.set_figure should be
clearly marked as a private method, not to be used except in
Axes.__init__().
Short of a major refactoring of mpl, I think you will need to find some
other way of accomplishing your ultimate aim.
Eric
> --
> Emmanuel
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