Ok, sounds like I'll have to copy what those do, as I'm not planning on
working with Cartesian or even curvilinear coordinates.
On Tue, Jun 30, 2015 at 11:36 AM, Benjamin Root <ben.r...@ou.edu> wrote:
> twinx()/twiny() I think is your best bet. It isn't a fully generic
> solution, but I think it addresses most needs.
>
> Ben Root
>
> On Mon, Jun 29, 2015 at 6:00 PM, T J <tjhn...@gmail.com> wrote:
>
>> When I read the transformations documentation:
>>
>>
>> http://matplotlib.org/devel/add_new_projection.html#creating-a-new-projection
>>
>> it seems like each projection is tied to an Axes instance. How might I
>> go about plotting two different projections on the same axes? Let's just
>> assume that the actual axes each projection draws is exactly same and all
>> that differs between to the two is how data is mapped to axis coordinates.
>>
>>
>>
>>
>> ------------------------------------------------------------------------------
>> Don't Limit Your Business. Reach for the Cloud.
>> GigeNET's Cloud Solutions provide you with the tools and support that
>> you need to offload your IT needs and focus on growing your business.
>> Configured For All Businesses. Start Your Cloud Today.
>> https://www.gigenetcloud.com/
>> _______________________________________________
>> Matplotlib-users mailing list
>> Matplotlib-users@lists.sourceforge.net
>> https://lists.sourceforge.net/lists/listinfo/matplotlib-users
>>
>>
>
------------------------------------------------------------------------------
Don't Limit Your Business. Reach for the Cloud.
GigeNET's Cloud Solutions provide you with the tools and support that
you need to offload your IT needs and focus on growing your business.
Configured For All Businesses. Start Your Cloud Today.
https://www.gigenetcloud.com/
_______________________________________________
Matplotlib-users mailing list
Matplotlib-users@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/matplotlib-users