Well, that would only be true if it were a completely ideal transformer with no impedance. Even at the nominal tap ratio of 1.0 the voltages magnitudes will not be identical (as with a transmission line).
Ray > On Oct 17, 2017, at 12:19 PM, Ahmad Sadiq Abubakar > <ahmad.abuba...@futminna.edu.ng> wrote: > > Dear Ray, > Thanks for your response. In my case, V1 is a generator bus with 1.025 p.u. > and V2 is a known PQ bus with 1 p.u. > This implied Tap is 1.02? > > On Oct 17, 2017 4:27 PM, "Ray Zimmerman" <r...@cornell.edu > <mailto:r...@cornell.edu>> wrote: > The tap ratio is the off-nominal tap ratio, relating per-unit voltages, not > kV voltages. So if both voltages are at their nominal values (i.e. both at 1 > p.u.) then the TAP should be 1 and SHIFT should be 0. > > Ray > > >> On Oct 17, 2017, at 6:23 AM, Ahmad Sadiq Abubakar >> <ahmad.abuba...@futminna.edu.ng <mailto:ahmad.abuba...@futminna.edu.ng>> >> wrote: >> >> Hi, all >> For a given case branch data r, x, b, assuming the branch is a transformer, >> between bus1 and bus2, with voltages V1 and V2 KV respectively. How do I >> obtain the Tap ration (column 9) and shift (column 10) of the branch matrix? >> >> I have simply used V1/V2 as the Tap ration while the shift is zero, however, >> the power flow did not converged. Am I missing something? >> >> Kindly assist >> >> best regrads >> A. A. Sadiq >> >
