Hi sir, Thanks for the suggestion!
Let me confirm my understanding: 1. Create a dummy generator with the following limits: -99999 MW <= Pdummy <= 99999 MW 2. To minimize the injection, set a very large positive cost coefficient (C = 99999Pdummy) and zero out all other costs, turning the objective function to: min (99999Pdummy + 0Pg1 + 0Pg2 + ...) 3. To maximize the injection, set a very large negative cost coefficient (C = -99999Pdummy) and zero out all other costs, turning the objective function to: min (-99999Pdummy + 0Pg1 + 0Pg2 + ...) 4. Retain all other information Thanks in advance! Cheers, Ronald On Tue, Oct 10, 2023 at 5:23 AM Ray Daniel Zimmerman <r...@cornell.edu> wrote: > You can do this by placing a dummy generator at the bus of interest and > using a very large negative (to maximize the injection) or positive (to > minimize the injection) generation cost. You can either zero out all other > costs, or simply make the magnitude of the cost large enough to dominate > all other costs. > > Ray > > > > On Oct 5, 2023, at 8:48 PM, Ronald Cabaoig <rrcaba...@up.edu.ph> wrote: > > > > Dear MATPOWER team, > > > > Greetings! > > > > In the current MATPOWER version, is it possible to reformulate the > objective function to find the maximum positive (and negative) power > injection in a certain bus: > > > > Maximize the positive power injection in bus X (or could also be: > minimize the negative power injection in bus X) > > Subject to the AC power flow equations, branch flow limits, generator > output limits, voltage limits. > > > > The main decision variable in this case would be the power injection in > bus X. Other values that could vary are the generator outputs, voltages, > and the like (all subject to the constraints). > > > > Cheers, > > Ronald > > > >
