On Fri, Aug 08, 2003 at 03:45:11 -0400, Pavel Roskin wrote: > > There's no thing like $[..] to evaluate expressions in POSIX sh, it's > > bash feature. sh uses $((..)) instead (and bash understands it too). > > Here comes fix. > > Does the next line work for you? I mean this: > > if (( $A < 10 )); then A="0$A"; fi
Yes, it works. I cannot find appropriate info in SUS (no free access to POSIX), so I don't know why. But it's supported by bash, zsh and pdksh (all linked and called by /bin/sh too). The last one is supposed to be POSIX-compliant, so if there's no problem with it, there should be no problem with any other. The '<' operator is legal in expr. > I think it's a much worse case of non-portable code. So maybe change it to: if [ $A -lt 10 ]; then A="0$A"; fi or even [ $A -lt 10 ] && A="0$A" ? > Have you tested your changes? Yes. -- Tom Pala <[EMAIL PROTECTED]> _______________________________________________ Mc-devel mailing list [EMAIL PROTECTED] http://mail.gnome.org/mailman/listinfo/mc-devel