2007/6/27, Steve Grimm <[EMAIL PROTECTED]>:
That's the "-n" option, not the "-s" option. I was correct about "-f". Sorry
if I confused anyone.
-Steve
On 6/27/07 11:00 AM, "Steve Grimm" <[EMAIL PROTECTED]> wrote:
> You can use the "-s" and "-f" options to change, respectively, the minimum
> chunk size (on which the other chunk sizes are based) and the multiplier
> that determines how many chunk sizes there are. The formula is
>
> chunk size(0) = whatever you specify with -s, plus space for object header
> chunk size(n) = chunk size(n-1) * multiplier specified with -f
>
> where each chunk size is rounded up to sizeof(void *) (8 bytes on a 64-bit
> system). So by playing with the -s and -f options you can fine-tune the
> sizing.
>
> -Steve
I understand your formula and now I have another question:
1) how many chunsize(i) memcached creates? Namely in your formula how
many is n_max?
