On 8/7/07 6:28 PM, "John.H" <[EMAIL PROTECTED]> spake:
> Thanks Ryan.
So what will happen when I open the -m option with a number
> larger than 2G?
By the way,is that mean if I run memcached in a 64-bit OS,I
> should not open
-m option larger than 4G?
2007/8/8, Ryan Ordway
> <[EMAIL PROTECTED]>:
>
> On 8/7/07 6:18 PM, "John.H"
> <[EMAIL PROTECTED]> spake:
>
> > So,in a 32-bit OS ,it does have the 2G
> barrier?
> Why?
> Can you give some detail
> > infomation?
> Thanks, Ask.
>
>
> 2007/8/8, Ask Bjørn Hansen
> > <[EMAIL PROTECTED]>:
>
> >
> >
> > On Aug 7,
> 2007, at 10:28, Brian P Brooks wrote:
>
> >
> > > Is there a reason why there
> is a 2G barrier?
>
> >
> > There isn't if you use a 64-bit OS.
>
>
>
> With a
> 32-bit OS, you cannot address more than 2GB of memory for a given
> process.
> Hence, the 2GB memory limit for memcached on a 32-bit OS.
>
>
Actually, I misspoke. The system itself is capable of addressing 4GB of RAM
with a 32-bit architecture. The 2GB limit is an OS imposed limit, depending
on your OS version. The 2.4 kernel had a 2GB/2GB split between kernel memory
and user space memory. Newer Linux kernels are able to address more. But you
still cannot address more than 2GB per process.
32-bit == 2^32 or ~ 4GB
64-bit == 2^64 or ~ 16 exabytes
64-bit OS/hardware gives you up to 17179869184 gigabytes or 16 exabytes of
addressable memory. I think you'll be good for a year or two, until the next
version of Windows comes out.
I've not tried it but you *might* be able to run multiple instances of
memcached on your system to utilize all of your memory. But remember that
the kernel needs memory too, so don't try to run a pair of 2GB memcached
instances. :-)
--
Ryan Ordway E-mail: [EMAIL PROTECTED]
Unix Systems Administrator [EMAIL PROTECTED]
OSU Libraries, Corvallis, OR 97370 Office: Valley Library #4657
