Thanks for the info Akhalesh.

On Mon, Oct 21, 2013 at 1:45 PM, Akhalesh Yadav <[email protected]
> wrote:

> *Hi Suresh,*
> *               You need to identify all the objects present at web page
> 1 and 2 then compare to each of them.*
> *1. Need to identify the total no. of visible links at page 1 and page 2
> using child object method.*
> *    if page1.childobjects(link) =page2.childobjects(link)*
> *      for i=0 to ubound(LinktextArr1)   *
> *        for j=0 to ubound(LinktextArr2)    *
> *           if linkTextArr1(i)=linkTextArr2(j) Then *
> *              Print "Link matched"*
> *           else*
> *              Print " Link does not matched"*
> *           End if*
> *        Next*
> *     Next*
> *   End if*
> *
> *
> *2. Need to identify the total no. of visible Text boxes at page 1 and
> page 2 using child object method..*
> *    compare page1.text box to page2.text box same like as step 1*
> *
> *
> *3.  Need to identify the total no. of visible broken links or image
> links at page 1 and page 2 using child object method.*
> *4.  Need to identify the total no. of visible buttons at page 1 and page
> 2 using child object method.*
> *5.  Need to identify the browser versions of page 1 and page 2 using
> child object method.*
> *     ETC.....*
> *
> *
> *I hope this is enough info for you if you have required more then plz
> describe in details your requirements.*
> *
> *
> *
> *
> *Thanks...*
> *Akhalesh Yadav*
>
>
>
>
> On Sat, Oct 19, 2013 at 2:56 PM, bhavin v patel <[email protected]>wrote:
>
>> what you need to compare between two pages? its title, url or name? you
>> can do
>>
>> if page1.GetRoProperty("name of property") =page2..GetRoProperty("name of
>> property") then
>>    pass
>> else
>>   fail
>> end if ..
>> you can get value of property into an arrays and compare two arrays also.
>>
>>
>> On Saturday, October 19, 2013 3:25:44 AM UTC-4, suresh varatharajan wrote:
>>>
>>> Hi Guys,
>>>
>>> How to compare two web page objects using QTP and how to find the page
>>> difference and Error (Page cannot be found).
>>>
>>> Please help me to solve the above issue.
>>> --
>>> Regards,
>>> Suresh.V
>>>
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>
>
>
> --
> Akhalesh yadav
> +919555717928
> +919310680659
>
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-- 
Regards,
Suresh.V
Ph:91-9940641701

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