Hi friends,
Thanks for [email protected] for giving me the solution..
i got result,by following the method mentioned below..
Public Function fncEvaluoCeroUno (v_cadena)
fncEvaluoCeroUno = "VALID"
For i = 1 To len(v_cadena)
codAsc = Asc(mid(v_cadena,i ,1))
If not(codAsc = 48 or codAsc = 49) Then
fncEvaluoCeroUno = "INVALID"
Exit For
End if
Next
End Function
On Sat, Feb 14, 2015 at 2:11 AM, Parke Kuntz <[email protected]> wrote:
> Prakash:
>
> Do you want to limit the values that can be entered to only be 0 or 1 do
> you just want to say the value is not a binary number?
>
> Using regular expressions might be the way to go.
>
> Parke
>
> On Thu, Feb 12, 2015 at 11:10 PM, Prakash Sethupathi <
> [email protected]> wrote:
>
>> Hi Parke,
>> Thanks for your response..
>> yes the number can be in binary.
>>
>> On Fri, Feb 13, 2015 at 5:36 AM, Parke Kuntz <[email protected]>
>> wrote:
>>
>>> Are you trying to say that only binary numbers are in the field?
>>>
>>> On Thu, Feb 12, 2015 at 6:05 AM, Prakash Sethupathi <
>>> [email protected]> wrote:
>>>
>>>>
>>>>
>>>> On Thu, Feb 12, 2015 at 4:34 PM, Prakash Sethupathi <
>>>> [email protected]> wrote:
>>>>
>>>>> Hi Friends,
>>>>> I need a program[it may be in any language] or explanation for
>>>>> below mentioned concepts.
>>>>>
>>>>> Concept:
>>>>> I have text column it contains only numeric value of any numbers.
>>>>> but when a user enter 0 or 1 the text column need to be valid. if
>>>>> else it not to be valid.
>>>>>
>>>>> Eg: 0 valid
>>>>> 1 valid
>>>>> 01 Valid
>>>>> 10 valid
>>>>>
>>>>> 20 invalid
>>>>> 02 invalid
>>>>>
>>>>> 100 valid
>>>>> 200 invalid
>>>>>
>>>>>
>>>>> Can any one give suggestion for me...
>>>>>
>>>>> Solution and results are more welcomed....
>>>>>
>>>>>
>>>>> --
>>>>> Regards,
>>>>> S Prakash
>>>>>
>>>>>
>>>>
>>>>
>>>> --
>>>> Regards,
>>>> S Prakash
>>>> 9094394616
>>>>
>>>> --
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>>>
>>>
>>>
>>> --
>>> Parke
>>> Cell: 770-842-0121
>>>
>>> --
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>>
>>
>>
>> --
>> Regards,
>> S Prakash
>> 9094394616
>>
>> --
>> --
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>
>
>
> --
> Parke
> Cell: 770-842-0121
>
> --
> --
> You received this message because you are subscribed to the Google
> "QTP - HP Quick Test Professional - Automated Software Testing"
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>
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--
Regards,
S Prakash
9094394616
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