Yes this will work, but this does not answer my question, how do I know
the index of the link? Some of the links have 3 to 4 duplicates.
Thanks
On Tuesday, January 3, 2017 at 2:34:17 AM UTC-5, Ravikiran wrote:
> Please try append with index:=0 in the link
> Browser("title:="&BrowserTitle, "name:="&BroswerName).Page("
> title:="&BroswerPageTitle).link("name:="& LinkName,"index:=0").click
>
> On Sat, Dec 31, 2016 at 1:23 AM, <[email protected] <javascript:>> wrote:
>
>> Hi,
>>
>>
>> I'm working on a website which has duplicate link names. When I run the
>> following code, the script fails when it reach the duplicate
>> link.(indicating there is
>> more than one name for this link). How can I handle this situation?
>> I'm guessing I should use index because that's unique for duplicate links.
>> How can I
>> get index?
>>
>>
>>
>> Set oLinkChild = Browser("title:="&BrowserTitle,
>> "name:="&BroswerName).Page("title:="&BroswerPageTitle).childobjects(oLink)
>> iCount = oLinkChild.count
>>
>> 'the following code fails when it reaches the duplicate link
>> For i = 0 to iCount - 1
>> Linkname = oLinkChild(i).GetROProperty("name")
>> Browser("title:="&BrowserTitle,
>> "name:="&BroswerName).Page("title:="&BroswerPageTitle).link("name:="&
>> LinkName).click
>> Next
>>
>>
>>
>> For i = 0 to iCount - 1
>> Linkname = oLinkChild(i).GetROProperty("name")
>> Index = oLinkChild(i).GetTOProperty("index") (this
>> doesn't get the index)
>> Browser("title:="&BrowserTitle,
>> "name:="&BroswerName).Page("title:="&BroswerPageTitle).link("name:="&
>> LinkName, "index:="&Index).click
>> Next
>>
>> Thank you for your help
>> Happy New Year
>>
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