Hi, I�m thinking about something the would probably be called a stage 2 for my P-1 factorer, i.e. the 3^(E*(p+x)) = 3^(E*p) * 3^(E+x) with x difference between subsequent primes. But I need to check for a factor after every of these steps, and a full-blown GCD would be far too slow. Is there another trick to find out whether two numbers have a common factor (without neccessarily finding the factor itself) ? Ciao, Alex.
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