On 29 Jun 99, at 18:06, Lucas Wiman wrote:
> Therefore, to find the first one with 10^7 digits, we find ceil(10^7/log_10(2))
> which is 33219281.
NO! The _correct_ formula is ceil((10^7-1)/log_10(2)) = 33219278.
The point is that 2^n have 1 decimal digit for n < 4 ;-)
As it happens, 33219278, 33219279 & 33219280 are all composite and
therefore are not contenders for generating a Mersenne prime.
33219281 _is_ prime, the status of 2^33219281 is (so far as I know)
not known at this time ... unless someone found a factor bigger than
my 2^40 search limit.
Regards
Brian Beesley
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