Mersenne Digest        Saturday, June 30 2001        Volume 01 : Number 865




----------------------------------------------------------------------

Date: Tue, 26 Jun 2001 09:47:52 +0100
From: Andy Hedges <[EMAIL PROTECTED]>
Subject: RE: Mersenne: Proth observations

Anyone have any idea why for k = 659 there are very little primes? In fact
for k up to 200000 there are none (I haven't found any in this range yet!).

Andy

- -----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]]
Sent: 23 June 2001 02:17
To: Gordon Bower; [EMAIL PROTECTED]
Subject: Re: Mersenne: Proth observations



    
     Gordon Bower <[EMAIL PROTECTED]> observes


> After seeing a post on this list a few weeks ago I decided to branch out
> and try a few ranges from Michael Hartley's page looking for k*2^n-1
> primes. I must say there is a bit of a thrill in actually discovering a
> new prime every day I run the program instead of proving two numbers a
> month composite. :)
 

> I assumed that one value of k was pretty much the same as any other as far
> as execution time and the chance of finding primes. To my surprise this
> turned out not to be so: On the P3-500, for "most" 650<k<750, it takes
> about 5 hours for 16000<n<32000 and 12 hours for 32000<n<48000 -- but for
> k=701 it took less than 2 and just over 6 hours, respectively. The
> phenomenon is reproducible, doesn't seem to be an artifact of other
> programs or reboots or suchlike. Any number theorists care to explain what
> is special about k=701 that makes it easy to check for primality?
> 

      Fix k = 701.  We check that

        If n == 1 (mod 2) then k*2^n == 1 (mod 3)
        If n == 0 (mod 4) then k*2^n == 1 (mod 5)
        If n == 6 (mod 8) then k*2^n == 1 (mod 17)
        If n == 0 (mod 3) then k*2^n == 1 (mod 7)

Therefore k*2^n - 1 can be prime only if n == 2 or 10 (mod 24).
We can eliminate more potential values of n using

        If n == 8  (mod 18) then k*2^n == 1 (mod 19)
        If n == 18 (mod 20) then k*2^n == 1 (mod 41)
        If n == 6  (mod 28) then k*2^n == 1 (mod 29)

Some congruences are redundant; for example

        If n == 6 (mod 12) then k*2^n == 1 (mod 13)

eliminates nothing new.  k = 701 has less such redundancy than 
the typical k.




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------------------------------

Date: Tue, 26 Jun 2001 10:09:23 +0100
From: Andy Hedges <[EMAIL PROTECTED]>
Subject: RE: Mersenne: Proth observations

Are all primes of this form probable primes of this form?

Andy

- -----Original Message-----
From: Hoogendoorn, Sander [mailto:[EMAIL PROTECTED]]
Sent: 23 June 2001 10:02
To: '[EMAIL PROTECTED]'
Subject: RE: Mersenne: Proth observations


Brian J. Beesley Wrote:

> My strategy is:

> (1) run Proth at medium priority in factoring only mode to eliminate 
> candidates with "small" factors;

For step 1 i use Newpgen. I think this is better configurable then proth in
how far or long you want to factor. Don't know which is the fastest of the
two.

> (2) on the same system, run PRP at low priority to check the 
> survivors from stage 1 for probable primes;
> (3) on a different system (normally running Prime95), run Proth at 
> medium priority to verify the probable primes. (If you don't have a 
> "spare" system it would be best to do this in a seperate directory so 
> as to save keep changing the Proth setup!)

> BTW so far _every_ probable prime I've found using PRP has been 
> accepted as a genuine prime by Proth, though this is certainly not 
> guaranteed.

Same here
 
> If you break the run down as above you will see that some values of k 
> yield a much smaller proportion of candidates for psuedo-prime 
> testing than others. Or, to put it another way, some values of k give 
> a much higher percentage of k.2^p-1 with "small" factors than others.

For some k's you have to test more the twice as many candidates in the same
range of n's

Sander
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------------------------------

Date: Tue, 26 Jun 2001 19:14:06 +0200
From: =?iso-8859-1?Q?Torbj=F6rn_Alm?= <[EMAIL PROTECTED]>
Subject: Re: Mersenne: Proth observations

Hi!

It is a general observation, that while some values for k give a good
harvest of new primes, others give very little.
This is obvious if you look at the tables of primes of the form k*2^n-1
in Riesel´s book on primes.

I have run thru a number of runs, and I have got from 0 to 8 primes.

Torbjörn Alm
[EMAIL PROTECTED]


- ----- Original Message -----
From: "Andy Hedges" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, June 26, 2001 10:47 AM
Subject: RE: Mersenne: Proth observations


> Anyone have any idea why for k = 659 there are very little primes? In fact
> for k up to 200000 there are none (I haven't found any in this range
yet!).
>
> Andy
>
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]
> Sent: 23 June 2001 02:17
> To: Gordon Bower; [EMAIL PROTECTED]
> Subject: Re: Mersenne: Proth observations
>
>
>
>
>      Gordon Bower <[EMAIL PROTECTED]> observes
>
>
> > After seeing a post on this list a few weeks ago I decided to branch out
> > and try a few ranges from Michael Hartley's page looking for k*2^n-1
> > primes. I must say there is a bit of a thrill in actually discovering a
> > new prime every day I run the program instead of proving two numbers a
> > month composite. :)
>
>
> > I assumed that one value of k was pretty much the same as any other as
far
> > as execution time and the chance of finding primes. To my surprise this
> > turned out not to be so: On the P3-500, for "most" 650<k<750, it takes
> > about 5 hours for 16000<n<32000 and 12 hours for 32000<n<48000 -- but
for
> > k=701 it took less than 2 and just over 6 hours, respectively. The
> > phenomenon is reproducible, doesn't seem to be an artifact of other
> > programs or reboots or suchlike. Any number theorists care to explain
what
> > is special about k=701 that makes it easy to check for primality?
> >
>
>       Fix k = 701.  We check that
>
>         If n == 1 (mod 2) then k*2^n == 1 (mod 3)
>         If n == 0 (mod 4) then k*2^n == 1 (mod 5)
>         If n == 6 (mod 8) then k*2^n == 1 (mod 17)
>         If n == 0 (mod 3) then k*2^n == 1 (mod 7)
>
> Therefore k*2^n - 1 can be prime only if n == 2 or 10 (mod 24).
> We can eliminate more potential values of n using
>
>         If n == 8  (mod 18) then k*2^n == 1 (mod 19)
>         If n == 18 (mod 20) then k*2^n == 1 (mod 41)
>         If n == 6  (mod 28) then k*2^n == 1 (mod 29)
>
> Some congruences are redundant; for example
>
>         If n == 6 (mod 12) then k*2^n == 1 (mod 13)
>
> eliminates nothing new.  k = 701 has less such redundancy than
> the typical k.
>
>
>
>
> _________________________________________________________________________
> Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm
> Mersenne Prime FAQ      -- http://www.tasam.com/~lrwiman/FAQ-mers
> _________________________________________________________________________
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> Mersenne Prime FAQ      -- http://www.tasam.com/~lrwiman/FAQ-mers
>


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------------------------------

Date: Tue, 26 Jun 2001 21:08:21 +0200 (MET DST)
From: [EMAIL PROTECTED]
Subject: RE: Mersenne: Proth observations

Andy Hedges <[EMAIL PROTECTED]> asks:

> Anyone have any idea why for k = 659 there are very little primes? In fact
> for k up to 200000 there are none (I haven't found any in this range yet!).

Let k = 659.

If n == 1 (mod 2) then k*2^n == 1 (mod 3)
If n == 2 (mod 4) then k*2^n == 1 (mod 5)
If n == 0 (mod 3) then k*2^n == 1 (mod 7)
If n == 4 (mod 12) then k*2^n == 1 (mod 13)
If n == 8 (mod 9) then k*2^n == 1 (mod 73)

Therefore, if k*2^n - 1 is prime, then n == 20 or 32 (mod 36).
Other useful congruences include

If n == 2 (mod 5) then k*2^n == 1 (mod 31)
if n == 0 (mod 23) then k*2^n == 1 (mod 47)

This doesm't explain the total lack of primes, but
shows that many potential n can be eliminated early.


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------------------------------

Date: Wed, 27 Jun 2001 18:27:36 +0200
From: Guillermo Ballester Valor <[EMAIL PROTECTED]>
Subject: Mersenne: New Glucas v.2.8a

Hi:

A new version of Glucas has been released. You can download the new
version source at sourceforge

        http://prdownloads.sourceforge.net/glucas/Glucas-2.8a.tar.gz

I will also be uploading precompiled binaries when possible. You can see
all the files at

        https://sourceforge.net/project/showfiles_php?group_id=24518

The new features from v.2b are:

        -Some improvements in computing the physical address from logical
addresses. It speed Glucas up about 3-5%.
    
        -The old option Y_MINIMUM to compute only the basic power of twiddle
factors has been optimized and it can save some additional 3-5% for some
machines.

        -The code has been prepared to begin the introduction of prefecth
hints. At the moment we only can enjoy with pentium3 and Athlon prefetch
features. It has improved the performance more than 15%. As example, for
Athlons Glucas v2.8a with roundoff check activated is as fast as mprime
v.20.6 with roundoff active. (the penalty to use the roundoff in Glucas
is only 2-4%). Obviously, last improvements introduced by G. Woltman in
his last 21.1 version make mprime faster :).

         -Selftest now has the roundoff check active during first 50
iterations. The second half of selftest has roundoff check disabled. So
we can see the timings with both options. 
 

For some additional information you can visit 

        http://glucas.sourceforge.net/

I would like to give public acknowledgments to all people who has help
me making this release possible. Special thanks to B.J. Beesley, Tom
Cage and Klaus Kastens by their suggestions and QA work. 


Regards.


Guillermo.

 
- -- 
Guillermo Ballester Valor
[EMAIL PROTECTED]
Granada (Spain)
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------------------------------

Date: Wed, 27 Jun 2001 21:11:12 +0200
From: =?iso-8859-1?Q?Torbj=F6rn_Alm?= <[EMAIL PROTECTED]>
Subject: Re: Mersenne: Proth observations

This is in line the the existence of Sirpinski numbers
(no primes exists) and Riesel numbers for k*2^n+1.
They are proved by means of congurences.

The following values of k have given an exceptional harvest:

753 (9 primes up to 48000),
755 (8 primes up to 48000),
765 (9 primes up to 48000).

Other good k-values are 783, 789, and 885.

I guess that a congurence analysis will find much fewer
eliminating congurences.

Torbjörn Alm


- ----- Original Message -----
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, June 26, 2001 9:08 PM
Subject: RE: Mersenne: Proth observations


>
> Andy Hedges <[EMAIL PROTECTED]> asks:
>
> > Anyone have any idea why for k = 659 there are very little primes? In
fact
> > for k up to 200000 there are none (I haven't found any in this range
yet!).
>
> Let k = 659.
>
> If n == 1 (mod 2) then k*2^n == 1 (mod 3)
> If n == 2 (mod 4) then k*2^n == 1 (mod 5)
> If n == 0 (mod 3) then k*2^n == 1 (mod 7)
> If n == 4 (mod 12) then k*2^n == 1 (mod 13)
> If n == 8 (mod 9) then k*2^n == 1 (mod 73)
>
> Therefore, if k*2^n - 1 is prime, then n == 20 or 32 (mod 36).
> Other useful congruences include
>
> If n == 2 (mod 5) then k*2^n == 1 (mod 31)
> if n == 0 (mod 23) then k*2^n == 1 (mod 47)
>
> This doesm't explain the total lack of primes, but
> shows that many potential n can be eliminated early.
>
>
> _________________________________________________________________________
> Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm
> Mersenne Prime FAQ      -- http://www.tasam.com/~lrwiman/FAQ-mers


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------------------------------

Date: Wed, 27 Jun 2001 22:46:19 +0200
From: "Hoogendoorn, Sander" <[EMAIL PROTECTED]>
Subject: RE: Mersenne: Proth observations

Andy Hedges wrote:
 
> Anyone have any idea why for k = 659 there are very little primes? In
> fact for k up to 200000 there are none (I haven't found any in this
> range yet!).

This number has bees searched till at least 270000
Take a look at http://www.prothsearch.net/rieselsearch.html
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------------------------------

Date: Wed, 27 Jun 2001 23:58:32 +0200
From: =?iso-8859-1?Q?Torbj=F6rn_Alm?= <[EMAIL PROTECTED]>
Subject: Re: Mersenne: Proth observations

Hi!

To do a congurence analysis is fairly simple by means of some
math program.

For k-values of interest, I generated k*2^n-1 for n=0 to 30.
Then I factored the values.
In this table, the cyclic behavior becomes very obvious.
A number of small factors will occur.
The table for 885 was interesting.
Out of 30 number, 14 were primes!

Torbjörn Alm

- ----- Original Message -----
From: "Torbjörn Alm" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, June 27, 2001 9:11 PM
Subject: Re: Mersenne: Proth observations


> This is in line the the existence of Sirpinski numbers
> (no primes exists) and Riesel numbers for k*2^n+1.
> They are proved by means of congurences.
>
> The following values of k have given an exceptional harvest:
>
> 753 (9 primes up to 48000),
> 755 (8 primes up to 48000),
> 765 (9 primes up to 48000).
>
> Other good k-values are 783, 789, and 885.
>
> I guess that a congurence analysis will find much fewer
> eliminating congurences.
>
> Torbjörn Alm
>
>
> ----- Original Message -----
> From: <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, June 26, 2001 9:08 PM
> Subject: RE: Mersenne: Proth observations
>
>
> >
> > Andy Hedges <[EMAIL PROTECTED]> asks:
> >
> > > Anyone have any idea why for k = 659 there are very little primes? In
> fact
> > > for k up to 200000 there are none (I haven't found any in this range
> yet!).
> >
> > Let k = 659.
> >
> > If n == 1 (mod 2) then k*2^n == 1 (mod 3)
> > If n == 2 (mod 4) then k*2^n == 1 (mod 5)
> > If n == 0 (mod 3) then k*2^n == 1 (mod 7)
> > If n == 4 (mod 12) then k*2^n == 1 (mod 13)
> > If n == 8 (mod 9) then k*2^n == 1 (mod 73)
> >
> > Therefore, if k*2^n - 1 is prime, then n == 20 or 32 (mod 36).
> > Other useful congruences include
> >
> > If n == 2 (mod 5) then k*2^n == 1 (mod 31)
> > if n == 0 (mod 23) then k*2^n == 1 (mod 47)
> >
> > This doesm't explain the total lack of primes, but
> > shows that many potential n can be eliminated early.
> >
> >
> >
_________________________________________________________________________
> > Unsubscribe & list info -- http://www.scruz.net/~luke/signup.htm
> > Mersenne Prime FAQ      -- http://www.tasam.com/~lrwiman/FAQ-mers
>
>
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>


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------------------------------

Date: Wed, 27 Jun 2001 17:41:48 -0500
From: "Tom Cage" <[EMAIL PROTECTED]>
Subject: Mersenne: Glucas for the Macintosh

       Glucas for the Macintosh

    by Guillermo Ballester Valor
http://glucas.sourceforge.net

Version 2.8a released on Wednesday, 27 June 2001


Clients for G3 and G4, Mac OS 9.1
along with complete source code and project may
be found at

http://www.belchfirecomputing.com/GIMPS/GIMPS.html



Tom


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------------------------------

Date: Wed, 27 Jun 2001 20:10:25 -0500
From: "Tom Cage" <[EMAIL PROTECTED]>
Subject: Mersenne: Glucas for Mac UNIX FreeBSD 4.4

       Glucas for Mac UNIX FreeBSD 4.4

    by Guillermo Ballester Valor
http://glucas.sourceforge.net

Version 2.8a released on Wednesday, 27 June 2001


    The UNIX/gcc version runs up to 16% faster than
the Mac OS 9/Codewarrior version.  The UNIX version
also supports full multitasking,

    Complete source code may be found at

http://www.belchfirecomputing.com/GIMPS/GIMPS.html

    Binaries on request.


Tom


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------------------------------

Date: Sat, 30 Jun 2001 20:16:36 +0200
From: "Guido Lorenzini" <[EMAIL PROTECTED]>
Subject: Mersenne: 33mio exponents

Today, during this wonderful Saturday, I've spent some time looking about
the Assigned Exponents Report file, in particular the one fixing the
situation at 30 Jun 2001 15:00 (Jun 30 2001  8:00AM Pacific), 6 PM here in
Italy. I would like to to make some preliminary remarks, 'cause my english,
surely all but not perfect, may easily misinterpreted: I'm writing to this
list just for satisfying some curiosities, and without any polemic spirit or
willing of crossing the swords with anybody!
1st observation:
the "beerman's" computer named SKA4 seems to work simultaneously on 4 33mio
exponents, since each exponent is getting iterations: how it come? If any
Cpu is best working on just one copy of prime95, even a dual cpu PC should
have 2 computer ID...You may see the same situation with DEJEFLATERIC of
netconx, but, once again, these are just examples.
2nd:
Sometimes it happens that an exp. is assigned to an unspecified computer ID
(for example, the account "kpgcfd", has some). Is it possible?
3rd:
Net_Force seems to have some wonderful machines, called (properly!)10MIL-X:
they are able to test (or factoring) dozen of 33mio exponents in 2 months
time or more! Any information about the processor of these machines? Or is
it relevant the fact bits? (60 or less for these exponents instead 68 or
more as usual)
4th:
netconx reserved 2,325 33mio exps on its computer ID DEJECHRISTIA, most of
them with 60 fact bits or less. It started getting 'em on June 20th at 4:59
AM, one each two minutes, till June 23th at 12:07 PM. Now it may be too long
to explain but this mass of 33mio exps. seems to be bounced like a ball from
an account to another (e.g. from kpgcfd, ID mac_233, on May to netconcx by
now); then these exponents, assigned in June to netconx to computer ID
DEJECHRISTIA, were assigned to the same account netconx, but to a machine
called BART, in April 7th. I really do not understand what's going on... Is
there anybody who may give me some infos about this?
I know I've stolen time enough, so nothing more to say but thank you to
anyone who may satisfy my curiosity and happy hunting to everybody.
Best regards from Italy!
Guido

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------------------------------

End of Mersenne Digest V1 #865
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