Given arbitrary k is it possible to find prime p such that 2kp+1 is a factor of M(p)?
There's a theorem by Euler which is relevent to this question - something to do with prime pairs p, 2p+1, but I don't recall the details. Regards Daran G. _________________________________________________________________________ Unsubscribe & list info -- http://www.ndatech.com/mersenne/signup.htm Mersenne Prime FAQ -- http://www.tasam.com/~lrwiman/FAQ-mers