What you want is:
p = mem_db.getas('parent[name:S,children[name:S]]')
i = p.append(name='a parent')
c[i].children.append(name='a child')
Yes, but you see, on Gordon's keyboard, "c" and "p" are mapped to the same scancode - on other keyboards, that last line is better written as:
p[i].children.append(name='a child')
-jpw <wink>
_______________________________________________ metakit mailing list - [EMAIL PROTECTED] http://www.equi4.com/mailman/listinfo/metakit
