Ok, let’s say this is the working assumption then.
There are more developments to come before defining the distance, so there is 
still time for more discussions.
_
Thierry

> Le 23 mai 2019 à 14:56, Mario Carneiro <[email protected]> a écrit :
> 
> Yes, that's exactly right. I agree that it's best to build the whole real 
> vector space in one go.
> 
>> On Thu, May 23, 2019 at 2:41 AM Thierry Arnoux <[email protected]> 
>> wrote:
>> Hi Mario,
>> 
>> Restating, just to make sure I understand:
>> 
>> Your proposal is a “metric geometry” builder, which would take a Tarski 
>> geometry, two reference points, and overwrite the ‘dist’ slot with a metric 
>> built from those two points. We could e.g. use sSet for that.
>> The resulting structure would still be a geometry (we would have to prove 
>> that of course), but ‘dist’ would have actual useful values in RR.
>> Ok, I assume this may work.
>> 
>> I believe we may also consider, with the same function, setting also 
>> * the group addition with a vector addition that considers points as vectors 
>> originating from 0 and 0 as the null element, 
>> * the scalars with the reals (Ccfld |’s RR)
>> * the scalar multiplication with vector multiplication.
>> I believe this should equip the geometry with a vector space structure.
>> 
>> BR,
>> _
>> Thierry
>> 
>>> Le 23 mai 2019 à 13:55, Mario Carneiro <[email protected]> a écrit :
>>> 
>>> The reason the congruence was put in the dist slot is so that if the space 
>>> happens to already have a proper metric, it will agree with the geometry by 
>>> definition. In this case, I think the most practically useful approach is 
>>> to just start saying "dist is a metric" at some point in the development. 
>>> You can say "but wait we've lost generality" and that's true, but the point 
>>> of "the construction" is to show that once you have all of Tarski's axioms 
>>> the space of possible distances is isomorphic to RR, so it's not actually a 
>>> loss to say that it is RR.
>>> 
>>> But somehow this is less than satisfying, since this is basically bringing 
>>> in a whole bunch more axioms unrelated to Tarski's, which are conservative 
>>> but we haven't shown it, so we've cheated in a sense. Where is the space 
>>> for a proof? What can be done is to have a structure builder that takes a 
>>> "pure-Tarski" geometric space and a unit segment in it, and produces a real 
>>> geometric space on the same set of points. Now you can prove that the 
>>> constructed real geometry is isomorphic to the original geometry, and the 
>>> unit segment has length 1 in the real geometry.
>>> 
>>>> On Thu, May 23, 2019 at 1:44 AM Thierry Arnoux <[email protected]> 
>>>> wrote:
>>>> Hi all,
>>>> 
>>>> Later on in the development of elementary geometry, we shall be able to 
>>>> define the “length” of a segment. This goes by comparing the segment with 
>>>> a reference unitary segment. The question is “where does the unitary 
>>>> segment come from?”. It is not part of Tarski’s axioms. I have two 
>>>> proposals here:
>>>> 
>>>> - I believe we will have to define this “Unit” as two new slots (one for a 
>>>> zero, one for a one), since they cannot be derived from other slots. One 
>>>> may also think about a way to introduce multi dimensional coordinates here.
>>>> 
>>>> - Thanks to those, we shall be able to derive a distance function. 
>>>> Retrospectively, I think the choice of ‘ dist ‘ for the congruence 
>>>> relation might be problematic here, since the constructed geometric 
>>>> distance shall really be the structure’s ‘ dist ‘ slot. It might be better 
>>>> to define a new slot for congruence, to avoid the conflict.
>>>> 
>>>> An alternative would be to define the distance builder as a function of 
>>>> the geometry and the two unit points, which itself builds a distance 
>>>> operation. This would be nearer to the development of Schwabhaeuser, who 
>>>> uses “oe” (0- Einheit) indices everywhere (ch14 and ch15), but seems more 
>>>> complicated. 
>>>> 
>>>> Any thoughts?
>>>> BR,
>>>> _
>>>> Thierry
>>>> 
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