Hi  Thierry  ,

this is the counter example

    climlimsupcex.1 $e    |- -. M e. ZZ $.
    climlimsupcex.2 $e   |- Z = ( ZZ>= ` M ) $.
    climlimsupcex.3 $e |- F = (/) $.
    $( Counterexample for ~ climlimsup , showing that the first hypothesis 
is 
       needed, if the empty set is a complex number (see ~ 0ncn and its 
       comment) $)
    climlimsupcex $p |- ( (/) e. CC -> ( F : Z --> RR /\ F e. dom ~~> /\ -. 
F ~~> ( limsup ` F ) ) ) 

As you can see, there's already a "weird" precondition (/) e. CC  , but if 
you read the comment for ~ 0ncn you'll immediately see why it's there

~ climlimsup is not  published yet

    $d F k m x $. $d M k m x $. $d Z k m x $. $d k m ph x $. 
    climlimsup.1 $e     |- ( ph -> M e. ZZ ) $.
    climlimsup.2 $e   |- Z = ( ZZ>= ` M ) $.
    climlimsup.3 $e    |- ( ph -> F : Z --> RR ) $.
    $( A sequence of real numbers converges if and only if it converges to 
its 
       superior limit. The first hypothesis is needed (see ~ climlimsupcex 
for 
       a counterexample) $)
    climlimsup $p  |- ( ph -> ( F e. dom ~~> <-> F ~~> ( limsup ` F ) ) ) $=

Anyway, for the time being, I'm going to change the counterexample in 

|- ( ( (/) e. CC /\ -. -oo e. CC ) -> ( F : Z --> RR /\ F e. dom ~~> /\ -. 
F ~~> ( limsup ` F ) ) ) 

I believe it does the job.

Thanks everyone for the precious help, as always.
Glauco



Il giorno giovedì 6 gennaio 2022 alle 04:54:19 UTC+1 Thierry Arnoux ha 
scritto:

> There are other definitions of infinity on the complex plane: Benoît has 
> for example defined the circle at infinity, with an infinite number of 
> points at infinity (see ~ bj-inftyexpidisj 
> <http://us2.metamath.org:88/mpeuni/bj-inftyexpidisj.html>), and the 
> (single) point at infinity of the complex projective line (~ df-bj-infty 
> <http://us2.metamath.org:88/mpeuni/df-bj-infty.html>). These might be 
> used as more general versions of infinity, and we could then identify the 
> current `+oo` and `-oo` with the corresponding points at infinity in 
> direction 0 and π.
>
> Glauco, can you give the actual counter example you tried to prove in the 
> first place?
> Isn't it possible to prove it within RR, using `abs`, without any need to 
> consider `CC`?
>

-- 
You received this message because you are subscribed to the Google Groups 
"Metamath" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
To view this discussion on the web visit 
https://groups.google.com/d/msgid/metamath/50abb4be-3870-4515-9636-52f0213a4b6cn%40googlegroups.com.

Reply via email to