Oops, sorry for the wrong line numbers. I opened the old version of the
file (the one before those extra fd/in).


On Thu, Mar 6, 2014 at 2:30 PM, Mauro Lopes <[email protected]> wrote:

> I see.
> The only clause that adds a 1 to the solution is in line 26. It takes the
> first number (in the example, n=2), takes the first n vars (line 34) and
> force their sum to be n, making all of them equal to 1. So there is no way
> to have a solution starting with (1 0)
>
>
> On Thu, Mar 6, 2014 at 2:13 PM, David Nolen <[email protected]>wrote:
>
>> On Thu, Mar 6, 2014 at 12:10 PM, Mauro Lopes <[email protected]>wrote:
>>
>>> (1 0 0 1) and (0 1 0 1) are wrong for me.
>>>
>>
>> But which portion of your program should disallow this? If I can identify
>> that it will be much simpler for me to determine the flaw in core.logic's
>> FD functionality. I've encountered bugs like this in the past - they almost
>> always boil down to some subtle problem around logic var aliasing. We have
>> a bunch of tests to check for this but it looks like you've come across a
>> case I've missed.
>>
>> Thanks,
>> David
>>
>>
>>> The idea is that, say, (f 8 [2 3]) should give me all ways of putting
>>> two sequences of ones (with sizes 2 and 3, in this order), separated by
>>> some zeros, in an 8-length row.
>>>
>>> It is like solving a one-row nonogram. Then I just use it for all rows
>>> and columns to make a full nonogram solver:
>>>
>>> http://github.com/maurolopes/nonogramsolver
>>>
>>> As I said, my program seems to be working now. I'm only giving you
>>> context so it is easier to understand my code and debug core.logic.
>>>
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