On 12/09/11 10:05, Paul de Weerd wrote:
echo does this. echo "$x $y"
Well, for the record, it has little to do with `echo' per se. This is merely normal shell argument parsing. Same thing would happen with print, printf, banner, ... /Alexander
Paul 'WEiRD' de Weerd On Fri, Dec 09, 2011 at 01:22:22AM -0700, Daniel Melameth wrote: | While I realize this might not be the best forum for this, it is the | ksh that is in base--and the official pdksh-5.2.14 has been abandoned | since '99. That said, I'm not too familiar with shell scripting, but | I'm giving it a spin and am having some issues with typeset that I'd | appreciate an appropriate clue stick with. | | $ cat temp | typeset -L32 x="string1" | y="string2" | echo $x $y | | $ sh temp | string1 string2 | | As far as I understand it, the output should look like the following, | but this is not the case: | | string1 string2 | | What am I missing here? I am using typeset in a similar fashion in | some while loops and it's working as expected, but the scenario above | has me perplexed. | | Thanks. |
