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ramrunner wrote:
> float a;
> int main()
> {
> for(;a<3;a+=0.1)
> printf("%f\n",a);
> return 1;
> }
> output :
> 0.000000
> 0.100000
> ....
> 2.700000
> 2.799999
> 2.899999
> 2.999999
> why does the add loses a decimal point?
float is so tricky...
Never use it for precision.
For example :
float a,b; if(a==b) {} may fail.
if( abs(a-b) < 0.00001 ) {} may work.
You may want to look ceil(3) and floor(3) as well.
Using printf("%.2f\n"a) works for me. Error depends on the precision.
I would rather use something like that :
int main(void)
{
int a=0;
for(a=0; a<30; a++)
printf("%f\n",a/10.); /* Do not forget the '.' */
/*or printf("%d.%d\n", a/10, a%10); depending on the
context. */
return 1;
}
cheers,
theo
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