According to the following webpage, http://www.shido.info/lisp/scheme_asg_e.html
(define var 1) (set! var (* var 10)) var => 10 However, I get the following output from mit-scheme, when I try the code. Would you please let me know what ';Value: 1' means? Is '1' the old value of 'var'? 1 ]=> (define var 1) ;Value: var 1 ]=> (set! var (* var 10)) ;Value: 1 1 ]=> (+ var 1) ;Value: 11 _______________________________________________ MIT-Scheme-users mailing list MIT-Scheme-users@gnu.org http://lists.gnu.org/mailman/listinfo/mit-scheme-users
