Hi Alex,
I would assume your first approach to work, given how we can get the control
points in world coordinates internally [1,2]. How did you notice that approach
not working? What did not fit?
Best,
Caspar
[1]
https://phabricator.mitk.org/source/mitk/browse/master/Modules/PlanarFigure/src/DataManagement/mitkPlanarFigure.cpp;ded9a12a0fdb8ae6b20771913e610e5dcd40f41b$256-262
[2]
https://phabricator.mitk.org/source/mitk/browse/master/Modules/Core/src/DataManagement/mitkPlaneGeometry.cpp;ded9a12a0fdb8ae6b20771913e610e5dcd40f41b$881-894
Von: Alex Rothberg [mailto:[email protected]]
Gesendet: Samstag, 30. September 2017 20:27
An: [email protected]
Betreff: [mitk-users] Converting PlanarLine to World Coordinates
I would like to convert the coordinates of a PlanarLine defined in a pf file to
world coordinates. I assumed that the way to do this was multiple the (x, y, 0)
of each control point by a transformation matrix specific by the
transformParam. That does not seem to work. Apparently I am just supposed to
add the origin to the control point. What am I misunderstanding with how the
planar figure / PlanarLine is represented in XML? These files are created using
MITK-GEM and stored in an mitk scene file.
Here is the pf file:
<?xml version="1.0" ?>
<Version
Writer="C:\MITK\build2013\MITK\Modules\PlanarFigure\src\IO\mitkPlanarFigureWriter.cpp"
CVSRevision="$Revision: 17055 $" FileVersion="1" />
<PlanarFigure type="PlanarLine">
<property key="closed" type="BoolProperty">
<bool value="false" />
</property>
<property key="initiallyplaced" type="BoolProperty">
<bool value="true" />
</property>
<ControlPoints>
<Vertex id="0" x="115.8695640182204" y="213.91333499194826" />
<Vertex id="1" x="112.39129840859526" y="44.347886522720955" />
</ControlPoints>
<Geometry>
<transformParam param0="0.958333313465118" param1="0" param2="0"
param3="0" param4="-0.958333313465118" param5="0" param6="0" param7="0"
param8="-6.50000047683716" param9="-112.320826202631"
param10="112.13685862045457" param11="29.695721817634535" />
<boundsParam bound0="0" bound1="240" bound2="0"
bound3="262.53344449978272" bound4="0" bound5="1" />
<Spacing x="0.958333313465118" y="0.958333313465118"
z="6.500000476837157" />
<Origin x="-112.320826202631" y="112.13685862045457"
z="29.695721817634535" />
</Geometry>
</PlanarFigure>
naively this was the matrix I tried to use:
array([[ 0.95833331, 0. , 0. , 0. ],
[ 0. , -0.95833331, 0. , 0. ],
[ 0. , 0. , -6.50000048, 0. ],
[-112.32082367, 112.13685608, 29.69572258, 1. ]])
however this is the matrix that actually works:
array([[ 1. , 0. , 0. , 0. ],
[ 0. , -1. , 0. , 0. ],
[ 0. , 0. , -1. , 0. ],
[-112.32082367, 112.13685608, 29.69572258, 1. ]])
Is there a more correct way of creating the second matrix other than setting
the on diagonal elements to (+1 or-1)? How do I do if the value should be +1 or
-1?
Thanks for the help,
Alex
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