Hi Gerd Some thoughts on this:
Dividing the \0 count by some factor between 3 and 6 should reduce the overall length of the strings. This is because there will be 0..7 bits free after each string To make the canonical tree: after using the standard algo to make a normal tree, just remember the count at each level and chuck the tree away. Then simply allocate chars, in decreasing frequency order, in previously levels, from root (and maybe high to low), much the same way as the decoder handles levels 6 and above. It might be that if you start with ordered list when building the initial tree, and get the inequalities right for when sums of lower levels are equal, you get the canonical tree, but this is just a guess. Happy new year Ticker _______________________________________________ mkgmap-dev mailing list mkgmap-dev@lists.mkgmap.org.uk https://www.mkgmap.org.uk/mailman/listinfo/mkgmap-dev
