>>>> my $uid = $s->uid; >>>> my $gid = $s->gid;
> Include yes, but how should it be coded. is apr_uid_current equivalent to the old s->server_uid/gid? if so, we could open up part of APR::User. --Geoff -- Reporting bugs: http://perl.apache.org/bugs/ Mail list info: http://perl.apache.org/maillist/modperl.html
