this.remove.delay.pass([10, this, [d]], this.remove) ?
On Nov 28, 6:29 pm, Sean McArthur <[email protected]> wrote: > Wont that start the timeout right then? > > Sean McArthur > On Nov 28, 2010 3:13 AM, "Arian" <[email protected]> wrote: > > > > > > > > > Or: > > > var e = this.remove.delay(10, this, [d]); > > > On Nov 28, 3:28 am, Sean McArthur <[email protected]> wrote: > >> var that = this; > >> var e = function() { > >> setTimeout(function() { > > >> that.remove(d); > > >> }, 10); > > >> } > >> On Sat, Nov 27, 2010 at 4:53 PM, Dailce <[email protected]> wrote: > >> > Sorry I'm such a noob lol > >> > The previous 1.2 code I have uses > > >> > var e = this.remove.create({ > >> > bind: this, > >> > arguments: [d], > >> > delay: 10 > >> > }); > > >> > I read the docs, but I don't understand how to rewrite this at all. > >> > If anyone could shed some light on the matter - thanks.
