Liu Idárraga <[email protected]> ha scritto:
Appreciated colleagues.
I have some doubts about the correct calculation of error in my data. I had
understood that the error corresponde to the proportion that represent the
SS of each effect (image / digitalization) in the SStotal; but I found in
the classical paper of Bayley & Byrnes 1990. Syst. Zool. 39(2):126 that the
way to calculate the percent of the measurement error is:
% ME = 100% s2 within / (s2 within - s2 among)
s2 within = MS within
but
s2 among = (MS among -MS within)/# replicates
I have the followed results for 71 ind in 2D, and 44 coord (66 - 4 -
18 semi landmarks)
Procrustes ANOVA para la forma: con g.l. corregidos
Efecto SS SS (%) MS df F p (param.)
Individuo 0,26857296 92,84 8,59709E-05 3124 25,97 <.0001
Imagen 0,01048868 3,63 3,31082E-06 3168 2,05 <.0001
Digitalización 0,01021206 3,53 1,61175E-06 6336
Total 0,28927370 100,00
My questions are:
1) Is correct to say that 3,63 and 3,53 are the errors of image and
digitalization?
2) Is the total error equal to 3,63 + 3,53 or I should calculate it with
the equations of Bayley & Byrnes 1990?
In advance, thanks a lot for the help.
Liu
Dear Liu,
Perhaps the best way to report this would be to say that 3.63% of the
total sum of squares is accounted for by/due to a certain term
(digitization, preparation)?
Best,
Carmelo
--
Carmelo Fruciano
Postdoctoral Fellow - Queensland University of Technology - Brisbane,
Australia
Honorary Fellow - University of Catania - Catania, Italy
e-mail [email protected]
http://www.fruciano.it/research/
--
MORPHMET may be accessed via its webpage at http://www.morphometrics.org
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