this will put 'i' on stack...
will make the code 'slower'...
...I'm getting paranoid I think with this issues :))
~d
On Friday 29 November 2002 17:41, Bill Knight wrote:
> How about declaring 'i' as volatile??
>
> volatile int i;
> for (i=0; i<N; i++)
> continue;
>
> Haven't tried this but just maybe...
>
> Regards
> -Bill Knight
> R O SoftWare
>
> On Fri, 29 Nov 2002 17:00:07 +0300, Dmitry wrote:
> >yes...
> >this drives me up the wall.
> >
> >try:
> > for (i=0;i<N;i++) asm("; loop %0" ::"r"(i));
> >
> >then gcc will probably not optimize the loop.
> >
> >On Friday 29 November 2002 16:55, Steve Underwood wrote:
> >> Hi Dmitry,
> >>
> >> I think this problem is for you.......
> >>
> >> I have a delay loop for a slow LCD interface. This includes the
> >> following routine:
> >>
> >> static __inline__ void delay_b(void)
> >> {
> >> int i;
> >>
> >> for (i = 90; i > 0; i--)
> >> __asm__ __volatile__("; loop");
> >> }
> >>
> >>
> >> Compiled with the current mspgcc, this is optimsed to nothing. I
> >> reported this problem before. It seemed to be fixed a week or two ago,
> >> but is now back. A slightly modified routine:
> >>
> >> static __inline__ void delay_b(void)
> >> {
> >> int i;
> >>
> >> for (i = 90; i > 0; i--)
> >> _NOP();
> >> }
> >>
> >> produces a single NOP instruction, and there is no reason why it should
> >> not. However, if you take away the __inline__ you get something
> >> unexpected. You get 30 nop instructions, with a loop around them to
> >> repeat them 3 times. This is correct, but not very efficient :-)
> >>
> >> The above effects are with -O2 optimisation.
> >>
> >> Regards,
> >> Steve
> >>
> >>
> >>
> >>
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