Re: [Mspgcc-users] Question about libgcc 16x16=>32 multiply

[Ralf Hildebrandt]

Grant Edwards wrote:
uint32_t r;
        
void foo(uint16_t u1, uint16_t u2)
  {
    r = (uint32_t)u1 * (uint32_t)u2;
  }

This will result in a 32x32 Bit Multiplication with the result cropped 
to 32 Bits.

Try:

r = (uint32_t)u1 * u2;

Smart compilers will then recognize, that you are demanding a 
16x16=>32Bit multiplication. This is a common problem of C-compilers and 
it is said that most of them recognize it this way.

Ralf